Check if two strings are equal or not after processing backspace

Posted by N.K. Chauhan on Mar 31, 2024

Given two strings, s1 and s2, containing regular characters as well as some "backspaces," represented by a "#" character.

The task is to check if the two strings are equal or not after processing the backspace characters.

Input: s = "ab#c", t = "ad#c" Output: true

Input: s = "ab##", t = "c#d#" Output: true

Input: s = "bxj##tw", t = "bxj###tw" Output: false


Method 1: Using Stack

This problem can be solved using a stack.

The idea is to traverse each string from left to right and check for the current character; if the current character is a "#" and the stack is not empty, pop an element; otherwise, push the current character into the stack.

Once two stacks are available for each string, check if these two stacks have the same characters and return true or false accordingly.


The time complexity of this solution is O(n+m) and space complexity is O(n+m).


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